How do you find ##lim (x+1)^(3/2)-x^(3/2)## as ##x->1^+##?
Project MGMT 402 M3A1 Discussion
September 30, 2017I need this to be done by monday
September 30, 2017##2 sqrt 2 – 1##
##lim_(x to 1^+) (x+1)^(3/2)-x^(3/2)##
The function is continuous through x = 1 so you can just plug in the value x = 1 to get ##2^(3/2) – 1 = sqrt 8 -1##
